Câu 44 đề thi thử 2021 chuyên Trần Phú Hải Phòng
- 10/03/2021
- 146 lượt xem
$$d(SA,BC)=\dfrac{12V_{SABC}}{\sqrt{4.SA^2.BC^2-(SB^2+AC^2-SC^2-AB^2)^2}}$$
$CH^2=AH^2+AC^2-2AH.AC.\cos 60^\circ$
$SH=CH\tan 60^\circ$
$SA^2=SH^2+HA^2=\dfrac{25}{9}$
$SB^2=SH^2+HB^2=\dfrac{22}{9}$
$SC^2=SH^2+HC^2=\dfrac{28}{9}$
$$d(SA,BC)=\dfrac{12\times \dfrac13\times SH\times \dfrac{\sqrt3}{4}}{\sqrt{4\times \dfrac{25}{9}-\left(\dfrac{22}{9}+1-\dfrac{28}{9}-1\right)^2}}$$
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